Base | Representation |
---|---|
bin | 11110101001110011010100… |
… | …100101001100011010011100 |
3 | 122200100002111110022202121102 |
4 | 132221303110211030122130 |
5 | 120132243033000204222 |
6 | 1154420410245052232 |
7 | 40252663411464200 |
oct | 3651632445143234 |
9 | 580302443282542 |
10 | 134814000006812 |
11 | 39a57329456955 |
12 | 13153a339b7078 |
13 | 5a2bba093c289 |
14 | 2541064d3cb00 |
15 | 108bc4c97ad92 |
hex | 7a9cd494c69c |
134814000006812 has 36 divisors (see below), whose sum is σ = 280825176111480. Its totient is φ = 56433767441184.
The previous prime is 134814000006793. The next prime is 134814000006893. The reversal of 134814000006812 is 218600000418431.
134814000006812 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1348140000068123 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7997974487 + ... + 7997991342.
It is an arithmetic number, because the mean of its divisors is an integer number (7800699336430).
Almost surely, 2134814000006812 is an apocalyptic number.
It is an amenable number.
134814000006812 is an abundant number, since it is smaller than the sum of its proper divisors (146011176104668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134814000006812 is a wasteful number, since it uses less digits than its factorization.
134814000006812 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15995965890 (or 15995965881 counting only the distinct ones).
The product of its (nonzero) digits is 36864, while the sum is 38.
The spelling of 134814000006812 in words is "one hundred thirty-four trillion, eight hundred fourteen billion, six thousand, eight hundred twelve".
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