Base | Representation |
---|---|
bin | 10011100111101010000… |
… | …010111100111110010111 |
3 | 11202220001221212212010211 |
4 | 103213222002330332113 |
5 | 134042204324444411 |
6 | 2511213402430251 |
7 | 166256632602202 |
oct | 23475202747627 |
9 | 4686057785124 |
10 | 1348251406231 |
11 | 47a876851924 |
12 | 199372802387 |
13 | 9a1a78055a2 |
14 | 49381984939 |
15 | 25110018221 |
hex | 139ea0bcf97 |
1348251406231 has 2 divisors, whose sum is σ = 1348251406232. Its totient is φ = 1348251406230.
The previous prime is 1348251406223. The next prime is 1348251406261. The reversal of 1348251406231 is 1326041528431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1348251406231 - 23 = 1348251406223 is a prime.
It is a super-2 number, since 2×13482514062312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1348251406261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674125703115 + 674125703116.
It is an arithmetic number, because the mean of its divisors is an integer number (674125703116).
Almost surely, 21348251406231 is an apocalyptic number.
1348251406231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1348251406231 is an equidigital number, since it uses as much as digits as its factorization.
1348251406231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138240, while the sum is 40.
The spelling of 1348251406231 in words is "one trillion, three hundred forty-eight billion, two hundred fifty-one million, four hundred six thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •