134831141 has 2 divisors, whose sum is σ = 134831142. Its totient is φ = 134831140.

The previous prime is 134831119. The next prime is 134831149. The reversal of 134831141 is 141138431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75864100 + 58967041 = 8710^2 + 7679^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134831141 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134831141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134831149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67415570 + 67415571.

It is an arithmetic number, because the mean of its divisors is an integer number (67415571).

Almost surely, 2^134831141 is an apocalyptic number.

It is an amenable number.

134831141 is a deficient number, since it is larger than the sum of its proper divisors (1).

134831141 is an equidigital number, since it uses as much as digits as its factorization.

134831141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 26.

The square root of 134831141 is about 11611.6812305540. The cubic root of 134831141 is about 512.7788097066.

Adding to 134831141 its reverse (141138431), we get a palindrome (275969572).

The spelling of 134831141 in words is "one hundred thirty-four million, eight hundred thirty-one thousand, one hundred forty-one".