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13483117 is a prime number
BaseRepresentation
bin110011011011…
…110001101101
3221101000100201
4303123301231
511422424432
61200553501
7222414244
oct63336155
927330321
1013483117
11767a07a
124622891
132a4109b
141b0d95b
1512b4ee7
hexcdbc6d

13483117 has 2 divisors, whose sum is σ = 13483118. Its totient is φ = 13483116.

The previous prime is 13483073. The next prime is 13483121. The reversal of 13483117 is 71138431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13147876 + 335241 = 3626^2 + 579^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13483117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13483157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6741558 + 6741559.

It is an arithmetic number, because the mean of its divisors is an integer number (6741559).

Almost surely, 213483117 is an apocalyptic number.

It is an amenable number.

13483117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13483117 is an equidigital number, since it uses as much as digits as its factorization.

13483117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2016, while the sum is 28.

The square root of 13483117 is about 3671.9364101248. The cubic root of 13483117 is about 238.0108567888.

It can be divided in two parts, 1348 and 3117, that added together give a triangular number (4465 = T94).

The spelling of 13483117 in words is "thirteen million, four hundred eighty-three thousand, one hundred seventeen".