Search a number
-
+
1348336807 is a prime number
BaseRepresentation
bin101000001011101…
…1111110010100111
310110222010121101021
41100113133302213
510230133234212
6341443312011
745261450046
oct12027376247
93428117337
101348336807
11632112444
1231767b607
1318646033c
14cb10455d
157d58c307
hex505dfca7

1348336807 has 2 divisors, whose sum is σ = 1348336808. Its totient is φ = 1348336806.

The previous prime is 1348336777. The next prime is 1348336811. The reversal of 1348336807 is 7086338431.

It is a strong prime.

It is an emirp because it is prime and its reverse (7086338431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1348336807 - 211 = 1348334759 is a prime.

It is a super-2 number, since 2×13483368072 = 3636024290221910498, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1348336897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674168403 + 674168404.

It is an arithmetic number, because the mean of its divisors is an integer number (674168404).

Almost surely, 21348336807 is an apocalyptic number.

1348336807 is a deficient number, since it is larger than the sum of its proper divisors (1).

1348336807 is an equidigital number, since it uses as much as digits as its factorization.

1348336807 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 290304, while the sum is 43.

The square root of 1348336807 is about 36719.7059764917. The cubic root of 1348336807 is about 1104.7553923052.

The spelling of 1348336807 in words is "one billion, three hundred forty-eight million, three hundred thirty-six thousand, eight hundred seven".