Base | Representation |
---|---|
bin | 10000000100101… |
… | …10011101110001 |
3 | 100101201021112002 |
4 | 20002112131301 |
5 | 234004142113 |
6 | 21213543345 |
7 | 3225033065 |
oct | 1002263561 |
9 | 311637462 |
10 | 134834033 |
11 | 6a123894 |
12 | 391a4b55 |
13 | 21c1bb69 |
14 | 13c9baa5 |
15 | bc85c58 |
hex | 8096771 |
134834033 has 2 divisors, whose sum is σ = 134834034. Its totient is φ = 134834032.
The previous prime is 134834009. The next prime is 134834047. The reversal of 134834033 is 330438431.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 133448704 + 1385329 = 11552^2 + 1177^2 .
It is an emirp because it is prime and its reverse (330438431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134834033 - 26 = 134833969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134833987 and 134834005.
It is not a weakly prime, because it can be changed into another prime (134834003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67417016 + 67417017.
It is an arithmetic number, because the mean of its divisors is an integer number (67417017).
Almost surely, 2134834033 is an apocalyptic number.
It is an amenable number.
134834033 is a deficient number, since it is larger than the sum of its proper divisors (1).
134834033 is an equidigital number, since it uses as much as digits as its factorization.
134834033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
The square root of 134834033 is about 11611.8057596569. The cubic root of 134834033 is about 512.7824758866.
The spelling of 134834033 in words is "one hundred thirty-four million, eight hundred thirty-four thousand, thirty-three".
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