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134834033 is a prime number
BaseRepresentation
bin10000000100101…
…10011101110001
3100101201021112002
420002112131301
5234004142113
621213543345
73225033065
oct1002263561
9311637462
10134834033
116a123894
12391a4b55
1321c1bb69
1413c9baa5
15bc85c58
hex8096771

134834033 has 2 divisors, whose sum is σ = 134834034. Its totient is φ = 134834032.

The previous prime is 134834009. The next prime is 134834047. The reversal of 134834033 is 330438431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133448704 + 1385329 = 11552^2 + 1177^2 .

It is an emirp because it is prime and its reverse (330438431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134834033 - 26 = 134833969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134833987 and 134834005.

It is not a weakly prime, because it can be changed into another prime (134834003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67417016 + 67417017.

It is an arithmetic number, because the mean of its divisors is an integer number (67417017).

Almost surely, 2134834033 is an apocalyptic number.

It is an amenable number.

134834033 is a deficient number, since it is larger than the sum of its proper divisors (1).

134834033 is an equidigital number, since it uses as much as digits as its factorization.

134834033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

The square root of 134834033 is about 11611.8057596569. The cubic root of 134834033 is about 512.7824758866.

The spelling of 134834033 in words is "one hundred thirty-four million, eight hundred thirty-four thousand, thirty-three".