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13485127 is a prime number
BaseRepresentation
bin110011011100…
…010001000111
3221101010010011
4303130101013
511423011002
61201011051
7222423145
oct63342107
927333104
1013485127
117680637
124623a87
132a41c86
141b10595
1512b58d7
hexcdc447

13485127 has 2 divisors, whose sum is σ = 13485128. Its totient is φ = 13485126.

The previous prime is 13485119. The next prime is 13485167. The reversal of 13485127 is 72158431.

13485127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (72158431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13485127 - 23 = 13485119 is a prime.

It is a super-2 number, since 2×134851272 = 363697300412258, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13485167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6742563 + 6742564.

It is an arithmetic number, because the mean of its divisors is an integer number (6742564).

Almost surely, 213485127 is an apocalyptic number.

13485127 is a deficient number, since it is larger than the sum of its proper divisors (1).

13485127 is an equidigital number, since it uses as much as digits as its factorization.

13485127 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6720, while the sum is 31.

The square root of 13485127 is about 3672.2100974754. The cubic root of 13485127 is about 238.0226833828.

It can be divided in two parts, 1348 and 5127, that multiplied together give a palindrome (6911196).

The spelling of 13485127 in words is "thirteen million, four hundred eighty-five thousand, one hundred twenty-seven".