Base | Representation |
---|---|
bin | 11001000111101011… |
… | …00000010000111001 |
3 | 1021210212112101202221 |
4 | 30203311200100321 |
5 | 210104422131413 |
6 | 10110114324041 |
7 | 655125133642 |
oct | 144365402071 |
9 | 37725471687 |
10 | 13486130233 |
11 | 57a0629284 |
12 | 2744589621 |
13 | 136c00ba24 |
14 | 91d1506c9 |
15 | 53de7a68d |
hex | 323d60439 |
13486130233 has 2 divisors, whose sum is σ = 13486130234. Its totient is φ = 13486130232.
The previous prime is 13486130191. The next prime is 13486130237. The reversal of 13486130233 is 33203168431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9590872489 + 3895257744 = 97933^2 + 62412^2 .
It is a cyclic number.
It is not a de Polignac number, because 13486130233 - 221 = 13484033081 is a prime.
It is a super-2 number, since 2×134861302332 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13486130237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6743065116 + 6743065117.
It is an arithmetic number, because the mean of its divisors is an integer number (6743065117).
Almost surely, 213486130233 is an apocalyptic number.
It is an amenable number.
13486130233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13486130233 is an equidigital number, since it uses as much as digits as its factorization.
13486130233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 13486130233 its reverse (33203168431), we get a palindrome (46689298664).
The spelling of 13486130233 in words is "thirteen billion, four hundred eighty-six million, one hundred thirty thousand, two hundred thirty-three".
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