Base | Representation |
---|---|
bin | 10011101000000010111… |
… | …110010010001100011111 |
3 | 11202221011002210221202011 |
4 | 103220002332102030133 |
5 | 134044033410102311 |
6 | 2511323102212051 |
7 | 166303201363342 |
oct | 23500276221437 |
9 | 4687132727664 |
10 | 1348669612831 |
11 | 47aa70922712 |
12 | 19946a884027 |
13 | 9a24334cc08 |
14 | 493c1328459 |
15 | 25136ac6321 |
hex | 13a02f9231f |
1348669612831 has 2 divisors, whose sum is σ = 1348669612832. Its totient is φ = 1348669612830.
The previous prime is 1348669612799. The next prime is 1348669612853. The reversal of 1348669612831 is 1382169668431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1348669612831 - 25 = 1348669612799 is a prime.
It is a super-2 number, since 2×13486696128312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1348669612861) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674334806415 + 674334806416.
It is an arithmetic number, because the mean of its divisors is an integer number (674334806416).
Almost surely, 21348669612831 is an apocalyptic number.
1348669612831 is a deficient number, since it is larger than the sum of its proper divisors (1).
1348669612831 is an equidigital number, since it uses as much as digits as its factorization.
1348669612831 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8957952, while the sum is 58.
The spelling of 1348669612831 in words is "one trillion, three hundred forty-eight billion, six hundred sixty-nine million, six hundred twelve thousand, eight hundred thirty-one".
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