Base | Representation |
---|---|
bin | 10011101000000100110… |
… | …110001011001001011011 |
3 | 11202221020021221200102102 |
4 | 103220010312023021123 |
5 | 134044114431304433 |
6 | 2511330143554015 |
7 | 166304032461353 |
oct | 23500466131133 |
9 | 4687207850372 |
10 | 1348701041243 |
11 | 47aa87639306 |
12 | 1994792bb90b |
13 | 9a249a050ca |
14 | 493c5589b63 |
15 | 251397334e8 |
hex | 13a04d8b25b |
1348701041243 has 2 divisors, whose sum is σ = 1348701041244. Its totient is φ = 1348701041242.
The previous prime is 1348701041209. The next prime is 1348701041257. The reversal of 1348701041243 is 3421401078431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1348701041243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1348701041197 and 1348701041206.
It is not a weakly prime, because it can be changed into another prime (1348701041203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674350520621 + 674350520622.
It is an arithmetic number, because the mean of its divisors is an integer number (674350520622).
Almost surely, 21348701041243 is an apocalyptic number.
1348701041243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1348701041243 is an equidigital number, since it uses as much as digits as its factorization.
1348701041243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 38.
The spelling of 1348701041243 in words is "one trillion, three hundred forty-eight billion, seven hundred one million, forty-one thousand, two hundred forty-three".
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