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1348845900151 is a prime number
BaseRepresentation
bin10011101000001101011…
…110110001000101110111
311202221121101112021111011
4103220031132301011313
5134044414022301101
62511352400453051
7166310441656501
oct23501536610567
94687541467434
101348845900151
11480051389a12
121994b991a187
139a270a23c39
14493da8d6d71
15251472e9751
hex13a0d7b1177

1348845900151 has 2 divisors, whose sum is σ = 1348845900152. Its totient is φ = 1348845900150.

The previous prime is 1348845900097. The next prime is 1348845900167. The reversal of 1348845900151 is 1510095488431.

It is a strong prime.

It is an emirp because it is prime and its reverse (1510095488431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1348845900151 - 213 = 1348845891959 is a prime.

It is a super-2 number, since 2×13488459001512 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1348845900095 and 1348845900104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1348845900851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674422950075 + 674422950076.

It is an arithmetic number, because the mean of its divisors is an integer number (674422950076).

Almost surely, 21348845900151 is an apocalyptic number.

1348845900151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1348845900151 is an equidigital number, since it uses as much as digits as its factorization.

1348845900151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 691200, while the sum is 49.

The spelling of 1348845900151 in words is "one trillion, three hundred forty-eight billion, eight hundred forty-five million, nine hundred thousand, one hundred fifty-one".