Base | Representation |
---|---|
bin | 111110110100101111… |
… | …0010111011010110011 |
3 | 110220020100122122200222 |
4 | 1331221132113122303 |
5 | 4202300332212344 |
6 | 141551201403255 |
7 | 12514166200652 |
oct | 1755136273263 |
9 | 426210578628 |
10 | 134913554099 |
11 | 52242203045 |
12 | 2219233952b |
13 | c950b570ac |
14 | 675bca7199 |
15 | 37993e15ee |
hex | 1f697976b3 |
134913554099 has 2 divisors, whose sum is σ = 134913554100. Its totient is φ = 134913554098.
The previous prime is 134913554029. The next prime is 134913554107. The reversal of 134913554099 is 990455319431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134913554099 - 212 = 134913550003 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 134913554099.
It is not a weakly prime, because it can be changed into another prime (134913554029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67456777049 + 67456777050.
It is an arithmetic number, because the mean of its divisors is an integer number (67456777050).
Almost surely, 2134913554099 is an apocalyptic number.
134913554099 is a deficient number, since it is larger than the sum of its proper divisors (1).
134913554099 is an equidigital number, since it uses as much as digits as its factorization.
134913554099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2624400, while the sum is 53.
The spelling of 134913554099 in words is "one hundred thirty-four billion, nine hundred thirteen million, five hundred fifty-four thousand, ninety-nine".
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