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1349150531 is a prime number
BaseRepresentation
bin101000001101010…
…0110011101000011
310111000122221121012
41100122212131003
510230340304111
6341512551135
745301406321
oct12032463503
93430587535
101349150531
11632618843
123179b24ab
13186686831
14cb276d11
157d69d48b
hex506a6743

1349150531 has 2 divisors, whose sum is σ = 1349150532. Its totient is φ = 1349150530.

The previous prime is 1349150527. The next prime is 1349150611. The reversal of 1349150531 is 1350519431.

It is a weak prime.

It is an emirp because it is prime and its reverse (1350519431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1349150531 - 22 = 1349150527 is a prime.

It is a super-2 number, since 2×13491505312 = 3640414310595163922, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1349150501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674575265 + 674575266.

It is an arithmetic number, because the mean of its divisors is an integer number (674575266).

Almost surely, 21349150531 is an apocalyptic number.

1349150531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1349150531 is an equidigital number, since it uses as much as digits as its factorization.

1349150531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 32.

The square root of 1349150531 is about 36730.7845138108. The cubic root of 1349150531 is about 1104.9775883199.

Adding to 1349150531 its reverse (1350519431), we get a palindrome (2699669962).

Subtracting 1349150531 from its reverse (1350519431), we obtain a square (1368900 = 11702).

The spelling of 1349150531 in words is "one billion, three hundred forty-nine million, one hundred fifty thousand, five hundred thirty-one".