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13492121 is a prime number
BaseRepresentation
bin110011011101…
…111110011001
3221101110201012
4303131332121
511423221441
61201103305
7222452426
oct63357631
927343635
1013492121
117685915
124627b35
132a45206
141b12d4d
1512b79eb
hexcddf99

13492121 has 2 divisors, whose sum is σ = 13492122. Its totient is φ = 13492120.

The previous prime is 13492117. The next prime is 13492123. The reversal of 13492121 is 12129431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11316496 + 2175625 = 3364^2 + 1475^2 .

It is a cyclic number.

It is not a de Polignac number, because 13492121 - 22 = 13492117 is a prime.

Together with 13492123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13492123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6746060 + 6746061.

It is an arithmetic number, because the mean of its divisors is an integer number (6746061).

Almost surely, 213492121 is an apocalyptic number.

It is an amenable number.

13492121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13492121 is an equidigital number, since it uses as much as digits as its factorization.

13492121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 432, while the sum is 23.

The square root of 13492121 is about 3673.1622615942. The cubic root of 13492121 is about 238.0638260661.

The spelling of 13492121 in words is "thirteen million, four hundred ninety-two thousand, one hundred twenty-one".