Base | Representation |
---|---|
bin | 11001001000011001… |
… | …00010100000100101 |
3 | 1021211021220012001101 |
4 | 30210030202200211 |
5 | 210112443344431 |
6 | 10110452000101 |
7 | 655230353632 |
oct | 144414424045 |
9 | 37737805041 |
10 | 13492168741 |
11 | 57a3a83087 |
12 | 2746600031 |
13 | 13703443cc |
14 | 91dc83189 |
15 | 53e76e961 |
hex | 324322825 |
13492168741 has 2 divisors, whose sum is σ = 13492168742. Its totient is φ = 13492168740.
The previous prime is 13492168663. The next prime is 13492168747. The reversal of 13492168741 is 14786129431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12621623716 + 870545025 = 112346^2 + 29505^2 .
It is an emirp because it is prime and its reverse (14786129431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13492168741 - 233 = 4902234149 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13492168691 and 13492168700.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13492168747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6746084370 + 6746084371.
It is an arithmetic number, because the mean of its divisors is an integer number (6746084371).
Almost surely, 213492168741 is an apocalyptic number.
It is an amenable number.
13492168741 is a deficient number, since it is larger than the sum of its proper divisors (1).
13492168741 is an equidigital number, since it uses as much as digits as its factorization.
13492168741 is an evil number, because the sum of its binary digits is even.
The product of its digits is 290304, while the sum is 46.
The spelling of 13492168741 in words is "thirteen billion, four hundred ninety-two million, one hundred sixty-eight thousand, seven hundred forty-one".
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