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134922240000 = 217335461
BaseRepresentation
bin111110110100111111…
…1100000000000000000
3110220020221222221112000
41331221333200000000
54202310043140000
6141552111504000
712514333055202
oct1755177400000
9426227887460
10134922240000
11522470a5979
1222195228000
13c9528a8792
14675d0c8772
15379a05a000
hex1f69fe0000

134922240000 has 720 divisors, whose sum is σ = 507739533840. Its totient is φ = 35389440000.

The previous prime is 134922239929. The next prime is 134922240007. The reversal of 134922240000 is 42229431.

134922240000 is a `hidden beast` number, since 1 + 34 + 9 + 222 + 400 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (720).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134922240007) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2211839970 + ... + 2211840030.

It is an arithmetic number, because the mean of its divisors is an integer number (705193797).

Almost surely, 2134922240000 is an apocalyptic number.

134922240000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134922240000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (253869766920).

134922240000 is an abundant number, since it is smaller than the sum of its proper divisors (372817293840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134922240000 is an frugal number, since it uses more digits than its factorization.

134922240000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 124 (or 71 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 134922240000 its reverse (42229431), we get a palindrome (134964469431).

The spelling of 134922240000 in words is "one hundred thirty-four billion, nine hundred twenty-two million, two hundred forty thousand".