1349403983 has 2 divisors, whose sum is σ = 1349403984. Its totient is φ = 1349403982.

The previous prime is 1349403973. The next prime is 1349403989. The reversal of 1349403983 is 3893049431.

It is a strong prime.

It is an emirp because it is prime and its reverse (3893049431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1349403983 is a prime.

It is a super-2 number, since 2×1349403983² = 3641782218672528578, which contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1349403989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674701991 + 674701992.

It is an arithmetic number, because the mean of its divisors is an integer number (674701992).

Almost surely, 2^1349403983 is an apocalyptic number.

1349403983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1349403983 is an equidigital number, since it uses as much as digits as its factorization.

1349403983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 279936, while the sum is 44.

The square root of 1349403983 is about 36734.2344822919. The cubic root of 1349403983 is about 1105.0467778427.

The spelling of 1349403983 in words is "one billion, three hundred forty-nine million, four hundred three thousand, nine hundred eighty-three".