Base | Representation |
---|---|
bin | 10011101000110110101… |
… | …011100010100111110001 |
3 | 11210000101120011121110122 |
4 | 103220312223202213301 |
5 | 134102323000131414 |
6 | 2511545131540025 |
7 | 166333534130135 |
oct | 23506653424761 |
9 | 4700346147418 |
10 | 1349537114609 |
11 | 480376578632 |
12 | 1996712ba615 |
13 | 9a350ca8488 |
14 | 494646253c5 |
15 | 25187d33b8e |
hex | 13a36ae29f1 |
1349537114609 has 2 divisors, whose sum is σ = 1349537114610. Its totient is φ = 1349537114608.
The previous prime is 1349537114581. The next prime is 1349537114707. The reversal of 1349537114609 is 9064117359431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1346307693025 + 3229421584 = 1160305^2 + 56828^2 .
It is a cyclic number.
It is not a de Polignac number, because 1349537114609 - 212 = 1349537110513 is a prime.
It is not a weakly prime, because it can be changed into another prime (1349537114209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674768557304 + 674768557305.
It is an arithmetic number, because the mean of its divisors is an integer number (674768557305).
Almost surely, 21349537114609 is an apocalyptic number.
It is an amenable number.
1349537114609 is a deficient number, since it is larger than the sum of its proper divisors (1).
1349537114609 is an equidigital number, since it uses as much as digits as its factorization.
1349537114609 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 53.
The spelling of 1349537114609 in words is "one trillion, three hundred forty-nine billion, five hundred thirty-seven million, one hundred fourteen thousand, six hundred nine".
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