Base | Representation |
---|---|
bin | 10011101000110110101… |
… | …101100010100110100001 |
3 | 11210000101121011020112202 |
4 | 103220312231202212201 |
5 | 134102323113420232 |
6 | 2511545151102545 |
7 | 166333541442344 |
oct | 23506655424641 |
9 | 4700347136482 |
10 | 1349537638817 |
11 | 4803768a6465 |
12 | 199671511a55 |
13 | 9a35112cc64 |
14 | 4946472045b |
15 | 25187dd9162 |
hex | 13a36b629a1 |
1349537638817 has 2 divisors, whose sum is σ = 1349537638818. Its totient is φ = 1349537638816.
The previous prime is 1349537638781. The next prime is 1349537638853. The reversal of 1349537638817 is 7188367359431.
Together with previous prime (1349537638781) it forms an Ormiston pair, because they use the same digits, order apart.
It is a balanced prime because it is at equal distance from previous prime (1349537638781) and next prime (1349537638853).
It can be written as a sum of positive squares in only one way, i.e., 1074852636001 + 274685002816 = 1036751^2 + 524104^2 .
It is a cyclic number.
It is not a de Polignac number, because 1349537638817 - 212 = 1349537634721 is a prime.
It is not a weakly prime, because it can be changed into another prime (1349537638217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674768819408 + 674768819409.
It is an arithmetic number, because the mean of its divisors is an integer number (674768819409).
Almost surely, 21349537638817 is an apocalyptic number.
It is an amenable number.
1349537638817 is a deficient number, since it is larger than the sum of its proper divisors (1).
1349537638817 is an equidigital number, since it uses as much as digits as its factorization.
1349537638817 is an evil number, because the sum of its binary digits is even.
The product of its digits is 91445760, while the sum is 65.
The spelling of 1349537638817 in words is "one trillion, three hundred forty-nine billion, five hundred thirty-seven million, six hundred thirty-eight thousand, eight hundred seventeen".
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