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1349537638817 is a prime number
BaseRepresentation
bin10011101000110110101…
…101100010100110100001
311210000101121011020112202
4103220312231202212201
5134102323113420232
62511545151102545
7166333541442344
oct23506655424641
94700347136482
101349537638817
114803768a6465
12199671511a55
139a35112cc64
144946472045b
1525187dd9162
hex13a36b629a1

1349537638817 has 2 divisors, whose sum is σ = 1349537638818. Its totient is φ = 1349537638816.

The previous prime is 1349537638781. The next prime is 1349537638853. The reversal of 1349537638817 is 7188367359431.

Together with previous prime (1349537638781) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1349537638781) and next prime (1349537638853).

It can be written as a sum of positive squares in only one way, i.e., 1074852636001 + 274685002816 = 1036751^2 + 524104^2 .

It is a cyclic number.

It is not a de Polignac number, because 1349537638817 - 212 = 1349537634721 is a prime.

It is not a weakly prime, because it can be changed into another prime (1349537638217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674768819408 + 674768819409.

It is an arithmetic number, because the mean of its divisors is an integer number (674768819409).

Almost surely, 21349537638817 is an apocalyptic number.

It is an amenable number.

1349537638817 is a deficient number, since it is larger than the sum of its proper divisors (1).

1349537638817 is an equidigital number, since it uses as much as digits as its factorization.

1349537638817 is an evil number, because the sum of its binary digits is even.

The product of its digits is 91445760, while the sum is 65.

The spelling of 1349537638817 in words is "one trillion, three hundred forty-nine billion, five hundred thirty-seven million, six hundred thirty-eight thousand, eight hundred seventeen".