Base | Representation |
---|---|
bin | 111110110101111111… |
… | …0000100100111110111 |
3 | 110220100021102200010111 |
4 | 1331223332010213313 |
5 | 4202342041421101 |
6 | 141555255003451 |
7 | 12515215100266 |
oct | 1755376044767 |
9 | 426307380114 |
10 | 134955420151 |
11 | 522638a8692 |
12 | 221a4369587 |
13 | c9597250c6 |
14 | 67636845dd |
15 | 379ce11251 |
hex | 1f6bf849f7 |
134955420151 has 2 divisors, whose sum is σ = 134955420152. Its totient is φ = 134955420150.
The previous prime is 134955420109. The next prime is 134955420161. The reversal of 134955420151 is 151024559431.
It is a strong prime.
It is an emirp because it is prime and its reverse (151024559431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134955420151 - 29 = 134955419639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134955420101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67477710075 + 67477710076.
It is an arithmetic number, because the mean of its divisors is an integer number (67477710076).
Almost surely, 2134955420151 is an apocalyptic number.
134955420151 is a deficient number, since it is larger than the sum of its proper divisors (1).
134955420151 is an equidigital number, since it uses as much as digits as its factorization.
134955420151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108000, while the sum is 40.
Adding to 134955420151 its reverse (151024559431), we get a palindrome (285979979582).
The spelling of 134955420151 in words is "one hundred thirty-four billion, nine hundred fifty-five million, four hundred twenty thousand, one hundred fifty-one".
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