Base | Representation |
---|---|
bin | 11001001000111010… |
… | …10010011110000011 |
3 | 1021211121011021000202 |
4 | 30210131102132003 |
5 | 210120104400431 |
6 | 10111130035415 |
7 | 655312601642 |
oct | 144435223603 |
9 | 37747137022 |
10 | 13496559491 |
11 | 57a65019a8 |
12 | 2747b78b6b |
13 | 1371220a9c |
14 | 9206a7359 |
15 | 53ed3a8cb |
hex | 324752783 |
13496559491 has 2 divisors, whose sum is σ = 13496559492. Its totient is φ = 13496559490.
The previous prime is 13496559481. The next prime is 13496559547. The reversal of 13496559491 is 19495569431.
It is an a-pointer prime, because the next prime (13496559547) can be obtained adding 13496559491 to its sum of digits (56).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13496559491 - 214 = 13496543107 is a prime.
It is not a weakly prime, because it can be changed into another prime (13496559431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6748279745 + 6748279746.
It is an arithmetic number, because the mean of its divisors is an integer number (6748279746).
Almost surely, 213496559491 is an apocalyptic number.
13496559491 is a deficient number, since it is larger than the sum of its proper divisors (1).
13496559491 is an equidigital number, since it uses as much as digits as its factorization.
13496559491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5248800, while the sum is 56.
The spelling of 13496559491 in words is "thirteen billion, four hundred ninety-six million, five hundred fifty-nine thousand, four hundred ninety-one".
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