Base | Representation |
---|---|
bin | 11001001001010100… |
… | …11100111000101111 |
3 | 1021211211122120021112 |
4 | 30210222130320233 |
5 | 210122000310111 |
6 | 10111332022235 |
7 | 655354122554 |
oct | 144452347057 |
9 | 37754576245 |
10 | 13500010031 |
11 | 57a8449392 |
12 | 274916197b |
13 | 1371b5b521 |
14 | 920d24a2b |
15 | 5402bce8b |
hex | 324a9ce2f |
13500010031 has 2 divisors, whose sum is σ = 13500010032. Its totient is φ = 13500010030.
The previous prime is 13500010021. The next prime is 13500010087. The reversal of 13500010031 is 13001000531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13500010031 - 26 = 13500009967 is a prime.
It is a super-2 number, since 2×135000100312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13500009988 and 13500010015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13500010021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750005015 + 6750005016.
It is an arithmetic number, because the mean of its divisors is an integer number (6750005016).
Almost surely, 213500010031 is an apocalyptic number.
13500010031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13500010031 is an equidigital number, since it uses as much as digits as its factorization.
13500010031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 14.
Adding to 13500010031 its reverse (13001000531), we get a palindrome (26501010562).
The spelling of 13500010031 in words is "thirteen billion, five hundred million, ten thousand, thirty-one".
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