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1350004041213 = 33512171281263
BaseRepresentation
bin10011101001010010100…
…000101110010111111101
311210001121002202221100120
4103221102200232113331
5134104302013304323
62512103331445153
7166351234005162
oct23512240562775
94701532687316
101350004041213
114805960a5493
121997817567b9
139a3c69506c9
14494aa64c069
15251b3d175e3
hex13a5282e5fd

1350004041213 has 8 divisors (see below), whose sum is σ = 1800011918208. Its totient is φ = 899999429184.

The previous prime is 1350004041179. The next prime is 1350004041227. The reversal of 1350004041213 is 3121404000531.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1350004041213 - 217 = 1350003910141 is a prime.

It is a super-2 number, since 2×13500040412132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350004040213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 413020 + ... + 1694282.

It is an arithmetic number, because the mean of its divisors is an integer number (225001489776).

Almost surely, 21350004041213 is an apocalyptic number.

It is an amenable number.

1350004041213 is a deficient number, since it is larger than the sum of its proper divisors (450007876995).

1350004041213 is a wasteful number, since it uses less digits than its factorization.

1350004041213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1632483.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 1350004041213 its reverse (3121404000531), we get a palindrome (4471408041744).

The spelling of 1350004041213 in words is "one trillion, three hundred fifty billion, four million, forty-one thousand, two hundred thirteen".

Divisors: 1 3 351217 1053651 1281263 3843789 450001347071 1350004041213