Base | Representation |
---|---|
bin | 10011101001010010100… |
… | …000101110010111111101 |
3 | 11210001121002202221100120 |
4 | 103221102200232113331 |
5 | 134104302013304323 |
6 | 2512103331445153 |
7 | 166351234005162 |
oct | 23512240562775 |
9 | 4701532687316 |
10 | 1350004041213 |
11 | 4805960a5493 |
12 | 1997817567b9 |
13 | 9a3c69506c9 |
14 | 494aa64c069 |
15 | 251b3d175e3 |
hex | 13a5282e5fd |
1350004041213 has 8 divisors (see below), whose sum is σ = 1800011918208. Its totient is φ = 899999429184.
The previous prime is 1350004041179. The next prime is 1350004041227. The reversal of 1350004041213 is 3121404000531.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1350004041213 - 217 = 1350003910141 is a prime.
It is a super-2 number, since 2×13500040412132 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1350004040213) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 413020 + ... + 1694282.
It is an arithmetic number, because the mean of its divisors is an integer number (225001489776).
Almost surely, 21350004041213 is an apocalyptic number.
It is an amenable number.
1350004041213 is a deficient number, since it is larger than the sum of its proper divisors (450007876995).
1350004041213 is a wasteful number, since it uses less digits than its factorization.
1350004041213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1632483.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 1350004041213 its reverse (3121404000531), we get a palindrome (4471408041744).
The spelling of 1350004041213 in words is "one trillion, three hundred fifty billion, four million, forty-one thousand, two hundred thirteen".
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