13500101250045 has 24 divisors (see below), whose sum is σ = 24417574436736. Its totient is φ = 6887008173408.

The previous prime is 13500101250037. The next prime is 13500101250179. The reversal of 13500101250045 is 54005210100531.

13500101250045 is a `hidden beast` number, since 1 + 3 + 50 + 0 + 101 + 2 + 500 + 4 + 5 = 666.

It is not a de Polignac number, because 13500101250045 - 2³ = 13500101250037 is a prime.

It is a super-2 number, since 2×13500101250045² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6521787009 + ... + 6521789078.

It is an arithmetic number, because the mean of its divisors is an integer number (1017398934864).

Almost surely, 2^{13500101250045} is an apocalyptic number.

13500101250045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13500101250045 is a deficient number, since it is larger than the sum of its proper divisors (10917473186691).

13500101250045 is a wasteful number, since it uses less digits than its factorization.

13500101250045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13043576121 (or 13043576118 counting only the distinct ones).

The product of its (nonzero) digits is 3000, while the sum is 27.

Adding to 13500101250045 its reverse (54005210100531), we get a palindrome (67505311350576).

The spelling of 13500101250045 in words is "thirteen trillion, five hundred billion, one hundred one million, two hundred fifty thousand, forty-five".