Base | Representation |
---|---|
bin | 10011101001010011001… |
… | …000110100110110010101 |
3 | 11210001121211120000111021 |
4 | 103221103020310312111 |
5 | 134104312211202433 |
6 | 2512104345041141 |
7 | 166351422240214 |
oct | 23512310646625 |
9 | 4701554500437 |
10 | 1350014553493 |
11 | 4805a1025521 |
12 | 1997851861b1 |
13 | 9a3c8b914a8 |
14 | 494abbc707b |
15 | 251b4be222d |
hex | 13a53234d95 |
1350014553493 has 2 divisors, whose sum is σ = 1350014553494. Its totient is φ = 1350014553492.
The previous prime is 1350014553487. The next prime is 1350014553497. The reversal of 1350014553493 is 3943554100531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1349960486884 + 54066609 = 1161878^2 + 7353^2 .
It is a cyclic number.
It is not a de Polignac number, because 1350014553493 - 29 = 1350014552981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1350014553497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675007276746 + 675007276747.
It is an arithmetic number, because the mean of its divisors is an integer number (675007276747).
Almost surely, 21350014553493 is an apocalyptic number.
It is an amenable number.
1350014553493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350014553493 is an equidigital number, since it uses as much as digits as its factorization.
1350014553493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486000, while the sum is 43.
The spelling of 1350014553493 in words is "one trillion, three hundred fifty billion, fourteen million, five hundred fifty-three thousand, four hundred ninety-three".
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