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13500193896113 is a prime number
BaseRepresentation
bin1100010001110100001001…
…0000101111011010110001
31202210121100201120011222112
43010131002100233122301
53232141344114133423
644413523051415105
72562233250513611
oct304350220573261
952717321504875
1013500193896113
114335444561211
121620517754495
1376c0a8034102
143495accbca41
1518628731aa78
hexc474242f6b1

13500193896113 has 2 divisors, whose sum is σ = 13500193896114. Its totient is φ = 13500193896112.

The previous prime is 13500193896107. The next prime is 13500193896127. The reversal of 13500193896113 is 31169839100531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10634564500624 + 2865629395489 = 3261068^2 + 1692817^2 .

It is a cyclic number.

It is not a de Polignac number, because 13500193896113 - 238 = 13225315989169 is a prime.

It is not a weakly prime, because it can be changed into another prime (13500193896313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750096948056 + 6750096948057.

It is an arithmetic number, because the mean of its divisors is an integer number (6750096948057).

Almost surely, 213500193896113 is an apocalyptic number.

It is an amenable number.

13500193896113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13500193896113 is an equidigital number, since it uses as much as digits as its factorization.

13500193896113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 524880, while the sum is 50.

The spelling of 13500193896113 in words is "thirteen trillion, five hundred billion, one hundred ninety-three million, eight hundred ninety-six thousand, one hundred thirteen".