Base | Representation |
---|---|
bin | 1100010001110100001001… |
… | …0000101111011010110001 |
3 | 1202210121100201120011222112 |
4 | 3010131002100233122301 |
5 | 3232141344114133423 |
6 | 44413523051415105 |
7 | 2562233250513611 |
oct | 304350220573261 |
9 | 52717321504875 |
10 | 13500193896113 |
11 | 4335444561211 |
12 | 1620517754495 |
13 | 76c0a8034102 |
14 | 3495accbca41 |
15 | 18628731aa78 |
hex | c474242f6b1 |
13500193896113 has 2 divisors, whose sum is σ = 13500193896114. Its totient is φ = 13500193896112.
The previous prime is 13500193896107. The next prime is 13500193896127. The reversal of 13500193896113 is 31169839100531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10634564500624 + 2865629395489 = 3261068^2 + 1692817^2 .
It is a cyclic number.
It is not a de Polignac number, because 13500193896113 - 238 = 13225315989169 is a prime.
It is not a weakly prime, because it can be changed into another prime (13500193896313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750096948056 + 6750096948057.
It is an arithmetic number, because the mean of its divisors is an integer number (6750096948057).
Almost surely, 213500193896113 is an apocalyptic number.
It is an amenable number.
13500193896113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13500193896113 is an equidigital number, since it uses as much as digits as its factorization.
13500193896113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 524880, while the sum is 50.
The spelling of 13500193896113 in words is "thirteen trillion, five hundred billion, one hundred ninety-three million, eight hundred ninety-six thousand, one hundred thirteen".
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