Base | Representation |
---|---|
bin | 1100010001110100001001… |
… | …0000101111011010111111 |
3 | 1202210121100201120012000001 |
4 | 3010131002100233122333 |
5 | 3232141344114134002 |
6 | 44413523051415131 |
7 | 2562233250513631 |
oct | 304350220573277 |
9 | 52717321505001 |
10 | 13500193896127 |
11 | 4335444561224 |
12 | 16205177544a7 |
13 | 76c0a8034113 |
14 | 3495accbca51 |
15 | 18628731aa87 |
hex | c474242f6bf |
13500193896127 has 2 divisors, whose sum is σ = 13500193896128. Its totient is φ = 13500193896126.
The previous prime is 13500193896113. The next prime is 13500193896197. The reversal of 13500193896127 is 72169839100531.
It is a weak prime.
It is an emirp because it is prime and its reverse (72169839100531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13500193896127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13500193896107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750096948063 + 6750096948064.
It is an arithmetic number, because the mean of its divisors is an integer number (6750096948064).
Almost surely, 213500193896127 is an apocalyptic number.
13500193896127 is a deficient number, since it is larger than the sum of its proper divisors (1).
13500193896127 is an equidigital number, since it uses as much as digits as its factorization.
13500193896127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2449440, while the sum is 55.
The spelling of 13500193896127 in words is "thirteen trillion, five hundred billion, one hundred ninety-three million, eight hundred ninety-six thousand, one hundred twenty-seven".
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