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13500243503 is a prime number
BaseRepresentation
bin11001001001010110…
…10101111000101111
31021211212002102112122
430210223111320233
5210122030243003
610111341023155
7655356114335
oct144453257057
937755072478
1013500243503
1157a859883a
122749254abb
131371c10886
14920d85b55
15540317238
hex324ad5e2f

13500243503 has 2 divisors, whose sum is σ = 13500243504. Its totient is φ = 13500243502.

The previous prime is 13500243479. The next prime is 13500243517. The reversal of 13500243503 is 30534200531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13500243503 - 210 = 13500242479 is a prime.

It is a super-2 number, since 2×135002435032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13500243563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750121751 + 6750121752.

It is an arithmetic number, because the mean of its divisors is an integer number (6750121752).

Almost surely, 213500243503 is an apocalyptic number.

13500243503 is a deficient number, since it is larger than the sum of its proper divisors (1).

13500243503 is an equidigital number, since it uses as much as digits as its factorization.

13500243503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 26.

The spelling of 13500243503 in words is "thirteen billion, five hundred million, two hundred forty-three thousand, five hundred three".