Base | Representation |
---|---|
bin | 1100010001110100100010… |
… | …1010010000111110010010 |
3 | 1202210121122012120100110002 |
4 | 3010131020222100332102 |
5 | 3232142104110003300 |
6 | 44413541444410002 |
7 | 2562236023146200 |
oct | 304351052207622 |
9 | 52717565510402 |
10 | 13500301250450 |
11 | 433549a116103 |
12 | 16205476a6902 |
13 | 76c0c43511a1 |
14 | 3495bd266070 |
15 | 1862919745d5 |
hex | c4748a90f92 |
13500301250450 has 36 divisors (see below), whose sum is σ = 29210243649642. Its totient is φ = 4628674713600.
The previous prime is 13500301250437. The next prime is 13500301250467. The reversal of 13500301250450 is 5405210300531.
It can be written as a sum of positive squares in 3 ways, for example, as 11969531009401 + 1530770241049 = 3459701^2 + 1237243^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 2755161071 + ... + 2755165970.
Almost surely, 213500301250450 is an apocalyptic number.
13500301250450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13500301250450 is an abundant number, since it is smaller than the sum of its proper divisors (15709942399192).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13500301250450 is a wasteful number, since it uses less digits than its factorization.
13500301250450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5510327067 (or 5510327055 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 13500301250450 its reverse (5405210300531), we get a palindrome (18905511550981).
The spelling of 13500301250450 in words is "thirteen trillion, five hundred billion, three hundred one million, two hundred fifty thousand, four hundred fifty".
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