Base | Representation |
---|---|
bin | 111110110111011010… |
… | …0011010100111011001 |
3 | 110220110121101011210121 |
4 | 1331232310122213121 |
5 | 4202441311023231 |
6 | 142004123313241 |
7 | 12516335303605 |
oct | 1755664324731 |
9 | 426417334717 |
10 | 135003220441 |
11 | 52288886761 |
12 | 221b837b821 |
13 | c9665c01bb |
14 | 6769b68505 |
15 | 37a2204311 |
hex | 1f6ed1a9d9 |
135003220441 has 2 divisors, whose sum is σ = 135003220442. Its totient is φ = 135003220440.
The previous prime is 135003220433. The next prime is 135003220519. The reversal of 135003220441 is 144022300531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128471348041 + 6531872400 = 358429^2 + 80820^2 .
It is a cyclic number.
It is not a de Polignac number, because 135003220441 - 23 = 135003220433 is a prime.
It is not a weakly prime, because it can be changed into another prime (135003280441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67501610220 + 67501610221.
It is an arithmetic number, because the mean of its divisors is an integer number (67501610221).
Almost surely, 2135003220441 is an apocalyptic number.
It is an amenable number.
135003220441 is a deficient number, since it is larger than the sum of its proper divisors (1).
135003220441 is an equidigital number, since it uses as much as digits as its factorization.
135003220441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 135003220441 its reverse (144022300531), we get a palindrome (279025520972).
The spelling of 135003220441 in words is "one hundred thirty-five billion, three million, two hundred twenty thousand, four hundred forty-one".
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