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135003331 is a prime number
BaseRepresentation
bin10000000101111…
…11110011000011
3100102000212202101
420002333303003
5234030101311
621221331231
73226336501
oct1002776303
9312025671
10135003331
116a22a001
1239266b17
1321c7ac38
1413d03671
15bcbaec1
hex80bfcc3

135003331 has 2 divisors, whose sum is σ = 135003332. Its totient is φ = 135003330.

The previous prime is 135003329. The next prime is 135003361. The reversal of 135003331 is 133300531.

135003331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 135003331 - 21 = 135003329 is a prime.

It is a super-2 number, since 2×1350033312 = 36451798762191122, which contains 22 as substring.

Together with 135003329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 135003299 and 135003308.

It is not a weakly prime, because it can be changed into another prime (135003311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67501665 + 67501666.

It is an arithmetic number, because the mean of its divisors is an integer number (67501666).

Almost surely, 2135003331 is an apocalyptic number.

135003331 is a deficient number, since it is larger than the sum of its proper divisors (1).

135003331 is an equidigital number, since it uses as much as digits as its factorization.

135003331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 405, while the sum is 19.

The square root of 135003331 is about 11619.0933811550. The cubic root of 135003331 is about 512.9970031756.

Adding to 135003331 its reverse (133300531), we get a palindrome (268303862).

The spelling of 135003331 in words is "one hundred thirty-five million, three thousand, three hundred thirty-one".