Base | Representation |
---|---|
bin | 11001001001011001… |
… | …00000101101001111 |
3 | 1021211212122222221011 |
4 | 30210230200231033 |
5 | 210122120044332 |
6 | 10111351350051 |
7 | 655361531662 |
oct | 144454405517 |
9 | 37755588834 |
10 | 13500549967 |
11 | 57a8788013 |
12 | 2749382327 |
13 | 1371cba208 |
14 | 9210256d9 |
15 | 540377e47 |
hex | 324b20b4f |
13500549967 has 2 divisors, whose sum is σ = 13500549968. Its totient is φ = 13500549966.
The previous prime is 13500549947. The next prime is 13500549971. The reversal of 13500549967 is 76994500531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13500549967 - 211 = 13500547919 is a prime.
It is a super-2 number, since 2×135005499672 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13500549967.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13500549947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750274983 + 6750274984.
It is an arithmetic number, because the mean of its divisors is an integer number (6750274984).
Almost surely, 213500549967 is an apocalyptic number.
13500549967 is a deficient number, since it is larger than the sum of its proper divisors (1).
13500549967 is an equidigital number, since it uses as much as digits as its factorization.
13500549967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1020600, while the sum is 49.
The spelling of 13500549967 in words is "thirteen billion, five hundred million, five hundred forty-nine thousand, nine hundred sixty-seven".
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