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13501000537 is a prime number
BaseRepresentation
bin11001001001011100…
…01110101101011001
31021211220111212222221
430210232032231121
5210122224004122
610111405144041
7655365416413
oct144456165531
937756455887
1013501000537
1157a8a65592
12274955b021
13137211731b
149211019b3
155404166c7
hex324b8eb59

13501000537 has 2 divisors, whose sum is σ = 13501000538. Its totient is φ = 13501000536.

The previous prime is 13501000507. The next prime is 13501000561. The reversal of 13501000537 is 73500010531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13276570176 + 224430361 = 115224^2 + 14981^2 .

It is an emirp because it is prime and its reverse (73500010531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13501000537 - 227 = 13366782809 is a prime.

It is not a weakly prime, because it can be changed into another prime (13501000507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750500268 + 6750500269.

It is an arithmetic number, because the mean of its divisors is an integer number (6750500269).

Almost surely, 213501000537 is an apocalyptic number.

It is an amenable number.

13501000537 is a deficient number, since it is larger than the sum of its proper divisors (1).

13501000537 is an equidigital number, since it uses as much as digits as its factorization.

13501000537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1575, while the sum is 25.

The spelling of 13501000537 in words is "thirteen billion, five hundred one million, five hundred thirty-seven", and thus it is an aban number.