Base | Representation |
---|---|
bin | 11001001001011100… |
… | …01110101101011001 |
3 | 1021211220111212222221 |
4 | 30210232032231121 |
5 | 210122224004122 |
6 | 10111405144041 |
7 | 655365416413 |
oct | 144456165531 |
9 | 37756455887 |
10 | 13501000537 |
11 | 57a8a65592 |
12 | 274955b021 |
13 | 137211731b |
14 | 9211019b3 |
15 | 5404166c7 |
hex | 324b8eb59 |
13501000537 has 2 divisors, whose sum is σ = 13501000538. Its totient is φ = 13501000536.
The previous prime is 13501000507. The next prime is 13501000561. The reversal of 13501000537 is 73500010531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13276570176 + 224430361 = 115224^2 + 14981^2 .
It is an emirp because it is prime and its reverse (73500010531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13501000537 - 227 = 13366782809 is a prime.
It is not a weakly prime, because it can be changed into another prime (13501000507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750500268 + 6750500269.
It is an arithmetic number, because the mean of its divisors is an integer number (6750500269).
Almost surely, 213501000537 is an apocalyptic number.
It is an amenable number.
13501000537 is a deficient number, since it is larger than the sum of its proper divisors (1).
13501000537 is an equidigital number, since it uses as much as digits as its factorization.
13501000537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1575, while the sum is 25.
The spelling of 13501000537 in words is "thirteen billion, five hundred one million, five hundred thirty-seven", and thus it is an aban number.
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