13501214433 has 64 divisors (see below), whose sum is σ = 23961907200. Its totient is φ = 7351585920.

The previous prime is 13501214431. The next prime is 13501214483. The reversal of 13501214433 is 33441210531.

It is a happy number.

13501214433 is a `hidden beast` number, since 13 + 5 + 0 + 1 + 214 + 433 = 666.

13501214433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13501214433 - 2¹ = 13501214431 is a prime.

It is a super-2 number, since 2×13501214433² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13501214397 and 13501214406.

It is not an unprimeable number, because it can be changed into a prime (13501214431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 312948 + ... + 353466.

It is an arithmetic number, because the mean of its divisors is an integer number (374404800).

Almost surely, 2^13501214433 is an apocalyptic number.

It is an amenable number.

13501214433 is a deficient number, since it is larger than the sum of its proper divisors (10460692767).

13501214433 is a wasteful number, since it uses less digits than its factorization.

13501214433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40619 (or 40613 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 13501214433 its reverse (33441210531), we get a palindrome (46942424964).

The spelling of 13501214433 in words is "thirteen billion, five hundred one million, two hundred fourteen thousand, four hundred thirty-three".