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13501303511342 = 210960616159011
BaseRepresentation
bin1100010001111000010001…
…1001100101100100101110
31202210201020001111110220212
43010132010121211210232
53232201132144330332
644414225130342422
72562302613214463
oct304360431454456
952721201443825
1013501303511342
114335963943599
12162078728aa12
1376c223ba047a
1434967640166a
151862ee9508b2
hexc478466592e

13501303511342 has 8 divisors (see below), whose sum is σ = 20251977032232. Its totient is φ = 6750644500600.

The previous prime is 13501303511341. The next prime is 13501303511393. The reversal of 13501303511342 is 24311530310531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13501303511299 and 13501303511308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13501303511341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 887384 + ... + 5271627.

It is an arithmetic number, because the mean of its divisors is an integer number (2531497129029).

Almost surely, 213501303511342 is an apocalyptic number.

13501303511342 is a deficient number, since it is larger than the sum of its proper divisors (6750673520890).

13501303511342 is a wasteful number, since it uses less digits than its factorization.

13501303511342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7255074.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 13501303511342 its reverse (24311530310531), we get a palindrome (37812833821873).

The spelling of 13501303511342 in words is "thirteen trillion, five hundred one billion, three hundred three million, five hundred eleven thousand, three hundred forty-two".

Divisors: 1 2 1096061 2192122 6159011 12318022 6750651755671 13501303511342