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135013877826301 is a prime number
BaseRepresentation
bin11110101100101101011110…
…001110100100001011111101
3122201001012102021201000221201
4132230231132032210023331
5120144031410210420201
61155052304052255501
740303300520065615
oct3654553616441375
9581035367630851
10135013877826301
113a024078257021
1213186716611591
135a449a584cb96
14254a9c6ad7a45
15109204a318801
hex7acb5e3a42fd

135013877826301 has 2 divisors, whose sum is σ = 135013877826302. Its totient is φ = 135013877826300.

The previous prime is 135013877826251. The next prime is 135013877826349. The reversal of 135013877826301 is 103628778310531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87189391800676 + 47824486025625 = 9337526^2 + 6915525^2 .

It is a cyclic number.

It is not a de Polignac number, because 135013877826301 - 215 = 135013877793533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135013877826601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67506938913150 + 67506938913151.

It is an arithmetic number, because the mean of its divisors is an integer number (67506938913151).

Almost surely, 2135013877826301 is an apocalyptic number.

It is an amenable number.

135013877826301 is a deficient number, since it is larger than the sum of its proper divisors (1).

135013877826301 is an equidigital number, since it uses as much as digits as its factorization.

135013877826301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5080320, while the sum is 55.

The spelling of 135013877826301 in words is "one hundred thirty-five trillion, thirteen billion, eight hundred seventy-seven million, eight hundred twenty-six thousand, three hundred one".