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1350202103 is a prime number
BaseRepresentation
bin101000001111010…
…0111001011110111
310111002122101002022
41100132213023313
510231122431403
6341551303355
745313346165
oct12036471367
93432571068
101350202103
11633176908
1231821ab5b
13186964373
14cb46c235
157d809d38
hex507a72f7

1350202103 has 2 divisors, whose sum is σ = 1350202104. Its totient is φ = 1350202102.

The previous prime is 1350202081. The next prime is 1350202109. The reversal of 1350202103 is 3012020531.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1350202103 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1350202109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675101051 + 675101052.

It is an arithmetic number, because the mean of its divisors is an integer number (675101052).

Almost surely, 21350202103 is an apocalyptic number.

1350202103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350202103 is an equidigital number, since it uses as much as digits as its factorization.

1350202103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 1350202103 is about 36745.0963122972. The cubic root of 1350202103 is about 1105.2645989748.

Adding to 1350202103 its reverse (3012020531), we get a palindrome (4362222634).

The spelling of 1350202103 in words is "one billion, three hundred fifty million, two hundred two thousand, one hundred three".