Base | Representation |
---|---|
bin | 11110101100110011101100… |
… | …000000011000011011100100 |
3 | 122201001211122101021202001011 |
4 | 132230303230000120123210 |
5 | 120144134042132040400 |
6 | 1155055330211112004 |
7 | 40303625063630614 |
oct | 3654635400303344 |
9 | 581054571252034 |
10 | 135020551440100 |
11 | 3a026992344927 |
12 | 13187a795a2604 |
13 | 5a454ca349ba1 |
14 | 254b05b172a44 |
15 | 10922db1608ba |
hex | 7accec0186e4 |
135020551440100 has 72 divisors (see below), whose sum is σ = 293310181474688. Its totient is φ = 53950062182400.
The previous prime is 135020551440043. The next prime is 135020551440119. The reversal of 135020551440100 is 1044155020531.
It is a super-2 number, since 2×1350205514401002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 816407617 + ... + 816572983.
Almost surely, 2135020551440100 is an apocalyptic number.
135020551440100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
135020551440100 is an abundant number, since it is smaller than the sum of its proper divisors (158289630034588).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135020551440100 is a wasteful number, since it uses less digits than its factorization.
135020551440100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174125 (or 174118 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 135020551440100 in words is "one hundred thirty-five trillion, twenty billion, five hundred fifty-one million, four hundred forty thousand, one hundred".
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