Base | Representation |
---|---|
bin | 1100010001111100000010… |
… | …1001100010010000111111 |
3 | 1202210210211111112010122210 |
4 | 3010133000221202100333 |
5 | 3232210214431400210 |
6 | 44414513315511503 |
7 | 2562336636044313 |
oct | 304370051422077 |
9 | 52723744463583 |
10 | 13502314325055 |
11 | 4336332482926 |
12 | 1620a098b8593 |
13 | 76c3554256aa |
14 | 349730765b43 |
15 | 18635d56ae20 |
hex | c47c0a6243f |
13502314325055 has 32 divisors (see below), whose sum is σ = 22106650807296. Its totient is φ = 7033593135744.
The previous prime is 13502314325021. The next prime is 13502314325069. The reversal of 13502314325055 is 55052341320531.
It is not a de Polignac number, because 13502314325055 - 213 = 13502314316863 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 28963389 + ... + 29425881.
It is an arithmetic number, because the mean of its divisors is an integer number (690832837728).
Almost surely, 213502314325055 is an apocalyptic number.
13502314325055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13502314325055 is a deficient number, since it is larger than the sum of its proper divisors (8604336482241).
13502314325055 is a wasteful number, since it uses less digits than its factorization.
13502314325055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 507807.
The product of its (nonzero) digits is 270000, while the sum is 39.
Adding to 13502314325055 its reverse (55052341320531), we get a palindrome (68554655645586).
The spelling of 13502314325055 in words is "thirteen trillion, five hundred two billion, three hundred fourteen million, three hundred twenty-five thousand, fifty-five".
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