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1350303414463 is a prime number
BaseRepresentation
bin10011101001100100010…
…110101111100010111111
311210002100222002200020201
4103221210112233202333
5134110410133230323
62512153144224331
7166361530434403
oct23514426574277
94702328080221
101350303414463
1148072a090aa3
12199845a6b0a7
139a44398c143
14494d82db103
15251d02508ad
hex13a645af8bf

1350303414463 has 2 divisors, whose sum is σ = 1350303414464. Its totient is φ = 1350303414462.

The previous prime is 1350303414457. The next prime is 1350303414533. The reversal of 1350303414463 is 3644143030531.

It is a weak prime.

It is an emirp because it is prime and its reverse (3644143030531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1350303414463 is a prime.

It is a super-2 number, since 2×13503034144632 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1350303454463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675151707231 + 675151707232.

It is an arithmetic number, because the mean of its divisors is an integer number (675151707232).

Almost surely, 21350303414463 is an apocalyptic number.

1350303414463 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350303414463 is an equidigital number, since it uses as much as digits as its factorization.

1350303414463 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 37.

Adding to 1350303414463 its reverse (3644143030531), we get a palindrome (4994446444994).

The spelling of 1350303414463 in words is "one trillion, three hundred fifty billion, three hundred three million, four hundred fourteen thousand, four hundred sixty-three".