Base | Representation |
---|---|
bin | 1100010001111110110000… |
… | …0011011101011101101100 |
3 | 1202210212201020210100201021 |
4 | 3010133230003131131230 |
5 | 3232213212342311140 |
6 | 44415113452023524 |
7 | 2562363660555145 |
oct | 304375403353554 |
9 | 52725636710637 |
10 | 13503042541420 |
11 | 4336676544633 |
12 | 1620b91761ba4 |
13 | 76c440263c53 |
14 | 34979d366acc |
15 | 1863a2463b4a |
hex | c47ec0dd76c |
13503042541420 has 48 divisors (see below), whose sum is σ = 28449256163328. Its totient is φ = 5383530164160.
The previous prime is 13503042541367. The next prime is 13503042541421. The reversal of 13503042541420 is 2414524030531.
It is not an unprimeable number, because it can be changed into a prime (13503042541421) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 123891469 + ... + 124000411.
It is an arithmetic number, because the mean of its divisors is an integer number (592692836736).
Almost surely, 213503042541420 is an apocalyptic number.
13503042541420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13503042541420 is an abundant number, since it is smaller than the sum of its proper divisors (14946213621908).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13503042541420 is a wasteful number, since it uses less digits than its factorization.
13503042541420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 129190 (or 129188 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 13503042541420 its reverse (2414524030531), we get a palindrome (15917566571951).
The spelling of 13503042541420 in words is "thirteen trillion, five hundred three billion, forty-two million, five hundred forty-one thousand, four hundred twenty".
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