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13503468227 is a prime number
BaseRepresentation
bin11001001001101111…
…01001001011000011
31021212002011021000212
430210313221023003
5210123341440402
610111534104335
7655425405014
oct144467511303
937762137025
1013503468227
1157aa3a05a7
12274a34b0ab
13137279c5b2
1492158500b
15540752952
hex324de92c3

13503468227 has 2 divisors, whose sum is σ = 13503468228. Its totient is φ = 13503468226.

The previous prime is 13503468221. The next prime is 13503468229. The reversal of 13503468227 is 72286430531.

13503468227 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13503468227 - 230 = 12429726403 is a prime.

Together with 13503468229, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13503468221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751734113 + 6751734114.

It is an arithmetic number, because the mean of its divisors is an integer number (6751734114).

Almost surely, 213503468227 is an apocalyptic number.

13503468227 is a deficient number, since it is larger than the sum of its proper divisors (1).

13503468227 is an equidigital number, since it uses as much as digits as its factorization.

13503468227 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 241920, while the sum is 41.

Adding to 13503468227 its reverse (72286430531), we get a palindrome (85789898758).

The spelling of 13503468227 in words is "thirteen billion, five hundred three million, four hundred sixty-eight thousand, two hundred twenty-seven".