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1350365442144 = 2531953139100493
BaseRepresentation
bin10011101001101000000…
…011010111000001100000
311210002112021211000020020
4103221220003113001200
5134111022023122034
62512203241513440
7166363212605205
oct23515003270140
94702467730206
101350365442144
114807610a7344
121998627a2880
139a453799004
1449502645cac
15251d5904249
hex13a680d7060

1350365442144 has 192 divisors, whose sum is σ = 3829062585600. Its totient is φ = 415371220992.

The previous prime is 1350365442119. The next prime is 1350365442157. The reversal of 1350365442144 is 4412445630531.

It is a super-2 number, since 2×13503654421442 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1350365442096 and 1350365442105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13387162 + ... + 13487654.

It is an arithmetic number, because the mean of its divisors is an integer number (19943034300).

Almost surely, 21350365442144 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1350365442144, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1914531292800).

1350365442144 is an abundant number, since it is smaller than the sum of its proper divisors (2478697143456).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1350365442144 is a wasteful number, since it uses less digits than its factorization.

1350365442144 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100717 (or 100709 counting only the distinct ones).

The product of its (nonzero) digits is 691200, while the sum is 42.

The spelling of 1350365442144 in words is "one trillion, three hundred fifty billion, three hundred sixty-five million, four hundred forty-two thousand, one hundred forty-four".