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1350400660283 is a prime number
BaseRepresentation
bin10011101001101010001…
…001101101001100111011
311210002121202002021102202
4103221222021231030323
5134111110032112113
62512210540420415
7166364121136043
oct23515211551473
94702552067382
101350400660283
11480779a71244
1219987254770b
139a45ab7a14c
14495071b2723
15251d8a5e258
hex13a6a26d33b

1350400660283 has 2 divisors, whose sum is σ = 1350400660284. Its totient is φ = 1350400660282.

The previous prime is 1350400660243. The next prime is 1350400660307. The reversal of 1350400660283 is 3820660040531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1350400660283 - 214 = 1350400643899 is a prime.

It is not a weakly prime, because it can be changed into another prime (1350400660243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675200330141 + 675200330142.

It is an arithmetic number, because the mean of its divisors is an integer number (675200330142).

Almost surely, 21350400660283 is an apocalyptic number.

1350400660283 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350400660283 is an equidigital number, since it uses as much as digits as its factorization.

1350400660283 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 38.

The spelling of 1350400660283 in words is "one trillion, three hundred fifty billion, four hundred million, six hundred sixty thousand, two hundred eighty-three".