Base | Representation |
---|---|
bin | 10011101001101010001… |
… | …001101101001100111011 |
3 | 11210002121202002021102202 |
4 | 103221222021231030323 |
5 | 134111110032112113 |
6 | 2512210540420415 |
7 | 166364121136043 |
oct | 23515211551473 |
9 | 4702552067382 |
10 | 1350400660283 |
11 | 480779a71244 |
12 | 19987254770b |
13 | 9a45ab7a14c |
14 | 495071b2723 |
15 | 251d8a5e258 |
hex | 13a6a26d33b |
1350400660283 has 2 divisors, whose sum is σ = 1350400660284. Its totient is φ = 1350400660282.
The previous prime is 1350400660243. The next prime is 1350400660307. The reversal of 1350400660283 is 3820660040531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1350400660283 - 214 = 1350400643899 is a prime.
It is not a weakly prime, because it can be changed into another prime (1350400660243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675200330141 + 675200330142.
It is an arithmetic number, because the mean of its divisors is an integer number (675200330142).
Almost surely, 21350400660283 is an apocalyptic number.
1350400660283 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350400660283 is an equidigital number, since it uses as much as digits as its factorization.
1350400660283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 38.
The spelling of 1350400660283 in words is "one trillion, three hundred fifty billion, four hundred million, six hundred sixty thousand, two hundred eighty-three".
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