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13504031031 = 312754796469
BaseRepresentation
bin11001001001110011…
…10010100100110111
31021212010012212001110
430210321302210313
5210124012443111
610111554130103
7655433240601
oct144471624467
937763185043
1013504031031
1157aa745427
12274a580933
13137293880a
14921690171
155408145a6
hex324e72937

13504031031 has 16 divisors (see below), whose sum is σ = 18153267200. Its totient is φ = 8928789408.

The previous prime is 13504031011. The next prime is 13504031033. The reversal of 13504031031 is 13013040531.

It is not a de Polignac number, because 13504031031 - 213 = 13504022839 is a prime.

It is a super-2 number, since 2×135040310312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13504030989 and 13504031007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13504031033) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2084265 + ... + 2090733.

It is an arithmetic number, because the mean of its divisors is an integer number (1134579200).

Almost surely, 213504031031 is an apocalyptic number.

13504031031 is a deficient number, since it is larger than the sum of its proper divisors (4649236169).

13504031031 is a wasteful number, since it uses less digits than its factorization.

13504031031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12078.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 13504031031 its reverse (13013040531), we get a palindrome (26517071562).

The spelling of 13504031031 in words is "thirteen billion, five hundred four million, thirty-one thousand, thirty-one".

Divisors: 1 3 127 381 5479 6469 16437 19407 695833 821563 2087499 2464689 35443651 106330953 4501343677 13504031031