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135040425133 is a prime number
BaseRepresentation
bin111110111000100001…
…0010101110010101101
3110220120012101101001011
41331301002111302231
54203030322101013
6142011532545221
712520266450235
oct1756102256255
9426505341034
10135040425133
11522a7888139
1222208922211
13c971218603
146770a90cc5
1537a5602c3d
hex1f71095cad

135040425133 has 2 divisors, whose sum is σ = 135040425134. Its totient is φ = 135040425132.

The previous prime is 135040425127. The next prime is 135040425137. The reversal of 135040425133 is 331524040531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77817565764 + 57222859369 = 278958^2 + 239213^2 .

It is a cyclic number.

It is not a de Polignac number, because 135040425133 - 225 = 135006870701 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135040425095 and 135040425104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135040425137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67520212566 + 67520212567.

It is an arithmetic number, because the mean of its divisors is an integer number (67520212567).

Almost surely, 2135040425133 is an apocalyptic number.

It is an amenable number.

135040425133 is a deficient number, since it is larger than the sum of its proper divisors (1).

135040425133 is an equidigital number, since it uses as much as digits as its factorization.

135040425133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 135040425133 its reverse (331524040531), we get a palindrome (466564465664).

The spelling of 135040425133 in words is "one hundred thirty-five billion, forty million, four hundred twenty-five thousand, one hundred thirty-three".