135042115203841 has 2 divisors, whose sum is σ = 135042115203842. Its totient is φ = 135042115203840.

The previous prime is 135042115203757. The next prime is 135042115203851. The reversal of 135042115203841 is 148302511240531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117581383815025 + 17460731388816 = 10843495^2 + 4178604^2 .

It is a cyclic number.

It is not a de Polignac number, because 135042115203841 - 2¹³ = 135042115195649 is a prime.

It is a super-3 number, since 3×135042115203841³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 135042115203794 and 135042115203803.

It is not a weakly prime, because it can be changed into another prime (135042115203851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67521057601920 + 67521057601921.

It is an arithmetic number, because the mean of its divisors is an integer number (67521057601921).

Almost surely, 2^{135042115203841} is an apocalyptic number.

It is an amenable number.

135042115203841 is a deficient number, since it is larger than the sum of its proper divisors (1).

135042115203841 is an equidigital number, since it uses as much as digits as its factorization.

135042115203841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 40.

The spelling of 135042115203841 in words is "one hundred thirty-five trillion, forty-two billion, one hundred fifteen million, two hundred three thousand, eight hundred forty-one".