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135042115220197 is a prime number
BaseRepresentation
bin11110101101000111110001…
…010011101011001011100101
3122201010220022012100021022021
4132231013301103223023211
5120200012222444021242
61155113254041503141
740305320335012303
oct3655076123531345
9581126265307267
10135042115220197
113a035048556a99
12131900971a1ab1
135a475559b8493
14254c105001273
151092b4e323b67
hex7ad1f14eb2e5

135042115220197 has 2 divisors, whose sum is σ = 135042115220198. Its totient is φ = 135042115220196.

The previous prime is 135042115220167. The next prime is 135042115220269. The reversal of 135042115220197 is 791022511240531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126243066810436 + 8799048409761 = 11235794^2 + 2966319^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135042115220197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135042115220167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67521057610098 + 67521057610099.

It is an arithmetic number, because the mean of its divisors is an integer number (67521057610099).

Almost surely, 2135042115220197 is an apocalyptic number.

It is an amenable number.

135042115220197 is a deficient number, since it is larger than the sum of its proper divisors (1).

135042115220197 is an equidigital number, since it uses as much as digits as its factorization.

135042115220197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 43.

The spelling of 135042115220197 in words is "one hundred thirty-five trillion, forty-two billion, one hundred fifteen million, two hundred twenty thousand, one hundred ninety-seven".