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1350434443201 is a prime number
BaseRepresentation
bin10011101001101100001…
…010100100111111000001
311210002201002122121212221
4103221230022210333001
5134111142204140301
62512214144451041
7166365011241364
oct23515412447701
94702632577787
101350434443201
11480797045908
12199881919a81
139a464b77c3c
144950b8880db
15251db9d3da1
hex13a6c2a4fc1

1350434443201 has 2 divisors, whose sum is σ = 1350434443202. Its totient is φ = 1350434443200.

The previous prime is 1350434443187. The next prime is 1350434443249. The reversal of 1350434443201 is 1023444340531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1198256433201 + 152178010000 = 1094649^2 + 390100^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350434443201 - 29 = 1350434442689 is a prime.

It is not a weakly prime, because it can be changed into another prime (1350434443291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675217221600 + 675217221601.

It is an arithmetic number, because the mean of its divisors is an integer number (675217221601).

Almost surely, 21350434443201 is an apocalyptic number.

It is an amenable number.

1350434443201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350434443201 is an equidigital number, since it uses as much as digits as its factorization.

1350434443201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 34.

Adding to 1350434443201 its reverse (1023444340531), we get a palindrome (2373878783732).

The spelling of 1350434443201 in words is "one trillion, three hundred fifty billion, four hundred thirty-four million, four hundred forty-three thousand, two hundred one".