Base | Representation |
---|---|
bin | 10011101001101100001… |
… | …010100100111111000001 |
3 | 11210002201002122121212221 |
4 | 103221230022210333001 |
5 | 134111142204140301 |
6 | 2512214144451041 |
7 | 166365011241364 |
oct | 23515412447701 |
9 | 4702632577787 |
10 | 1350434443201 |
11 | 480797045908 |
12 | 199881919a81 |
13 | 9a464b77c3c |
14 | 4950b8880db |
15 | 251db9d3da1 |
hex | 13a6c2a4fc1 |
1350434443201 has 2 divisors, whose sum is σ = 1350434443202. Its totient is φ = 1350434443200.
The previous prime is 1350434443187. The next prime is 1350434443249. The reversal of 1350434443201 is 1023444340531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1198256433201 + 152178010000 = 1094649^2 + 390100^2 .
It is a cyclic number.
It is not a de Polignac number, because 1350434443201 - 29 = 1350434442689 is a prime.
It is not a weakly prime, because it can be changed into another prime (1350434443291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675217221600 + 675217221601.
It is an arithmetic number, because the mean of its divisors is an integer number (675217221601).
Almost surely, 21350434443201 is an apocalyptic number.
It is an amenable number.
1350434443201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350434443201 is an equidigital number, since it uses as much as digits as its factorization.
1350434443201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 1350434443201 its reverse (1023444340531), we get a palindrome (2373878783732).
The spelling of 1350434443201 in words is "one trillion, three hundred fifty billion, four hundred thirty-four million, four hundred forty-three thousand, two hundred one".
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