Base | Representation |
---|---|
bin | 111110111000101000… |
… | …0111011111000100011 |
3 | 110220120110120202101021 |
4 | 1331301100323320203 |
5 | 4203032312014141 |
6 | 142012150550311 |
7 | 12520344123664 |
oct | 1756120737043 |
9 | 426513522337 |
10 | 135044251171 |
11 | 522a9a60755 |
12 | 2220a068397 |
13 | c971c57c3b |
14 | 67713a936b |
15 | 37a5b0b6d1 |
hex | 1f7143be23 |
135044251171 has 2 divisors, whose sum is σ = 135044251172. Its totient is φ = 135044251170.
The previous prime is 135044251127. The next prime is 135044251189. The reversal of 135044251171 is 171152440531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135044251171 - 221 = 135042154019 is a prime.
It is a super-2 number, since 2×1350442511712 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (135044291171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67522125585 + 67522125586.
It is an arithmetic number, because the mean of its divisors is an integer number (67522125586).
Almost surely, 2135044251171 is an apocalyptic number.
135044251171 is a deficient number, since it is larger than the sum of its proper divisors (1).
135044251171 is an equidigital number, since it uses as much as digits as its factorization.
135044251171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16800, while the sum is 34.
The spelling of 135044251171 in words is "one hundred thirty-five billion, forty-four million, two hundred fifty-one thousand, one hundred seventy-one".
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